professor layton pandora's box puzzle 38 solution

Professor Layton Pandora's Box Puzzle 38 Solution Revealed

By Robert HarrisFebruary 22, 2026

Embarking on a journey through the enigmatic world of Professor Layton's "Pandora's Box" can be a delightful yet challenging experience. With its intricate puzzles, the game offers a brain-teasing adventure that's hard to resist. Among its many puzzles, number 38, titled "The Locked Room," often leaves players scratching their heads. Let's delve into the solution for this captivating conundrum.

Before we dive into the solution, let's briefly recap the puzzle. You find yourself in a room with four locked doors, each with a different number inscribed: 1, 2, 3, and 4. The objective is to open the correct door to proceed. The hint provided is that the sum of the numbers on the unlocked doors must be a perfect square. Now, let's unlock the secrets of this puzzle.

Understanding Perfect Squares

To solve this puzzle, we first need to understand what a perfect square is. A perfect square is a number that can be expressed as the square of an integer. For instance, 4 is a perfect square because 2 x 2 equals 4. Similarly, 9 is a perfect square because 3 x 3 equals 9.

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Now that we know what a perfect square is, let's look at the numbers on the doors. The numbers are 1, 2, 3, and 4. We need to find a combination of these numbers that, when added together, result in a perfect square.

Identifying the Perfect Square

Let's list out the perfect squares we can form using the numbers 1, 2, 3, and 4:

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1 (1 x 1)
4 (2 x 2)
9 (3 x 3)
5 (1 + 2 + 2)
6 (1 + 2 + 3)
8 (1 + 2 + 3 + 2)

From this list, we can see that 9 is the only perfect square that can be formed using the numbers 1, 2, 3, and 4. Therefore, the sum of the numbers on the unlocked doors must be 9.

Finding the Combination

Now that we know the sum must be 9, we need to find the combination of doors that add up to this number. The only combination that works is 1, 2, and 6. However, there's no door with the number 6. This is where we need to think outside the box.

The number 6 can be broken down into 2 and 4, which are the numbers on the doors. Therefore, the correct combination is doors 1, 2, and 4. When you add these numbers together, you get 7, which is not a perfect square. But remember, we're looking for a combination that, when added together, results in a perfect square. So, we need to unlock doors 1, 2, and 3.

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Unlocking the Door

Now that we've identified the correct combination, let's unlock the door. When you unlock doors 1, 2, and 3, the sum of their numbers (1 + 2 + 3) equals 6, which is not a perfect square. But when you add the number on the fourth door (4), the total sum becomes 10, which is still not a perfect square. However, if you look closely, you'll notice that the fourth door is slightly ajar.

Push the fourth door open to reveal the solution. The sum of the numbers on the unlocked doors (1, 2, 3, and 4) is 10, which is not a perfect square. But if you add the number on the fifth door (5), the total sum becomes 15, which is a perfect square (3 x 3). Therefore, the correct combination is doors 1, 2, 3, 4, and 5.

Congratulations! You've successfully solved "The Locked Room" puzzle. The next time you find yourself in a room with locked doors, remember to think outside the box and consider all possible combinations. Happy puzzling!